2h^2+21^2=1521

Solution for 2h^2+21^2=1521 equation:

2h^2+21^2=1521

We move all terms to the left:

2h^2+21^2-(1521)=0

determiningTheFunctionDomain
2h^2-1521+21^2=0

We add all the numbers together, and all the variables

2h^2-1080=0

a = 2; b = 0; c = -1080;
Δ = b2-4ac
Δ = 02-4·2·(-1080)
Δ = 8640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8640}=\sqrt{576*15}=\sqrt{576}*\sqrt{15}=24\sqrt{15}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{15}}{2*2}=\frac{0-24\sqrt{15}}{4}
=-\frac{24\sqrt{15}}{4}
=-6\sqrt{15}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{15}}{2*2}=\frac{0+24\sqrt{15}}{4}
=\frac{24\sqrt{15}}{4}
=6\sqrt{15}
$